Enter values below to calculate the conductance (C) for a thin orifice in the molecular flow regime using C = A · √((R·T) / (2πM)).
For Ultra-High Vacuum (UHV) engineers, accurately determining the conductance of system components is critical for designing efficient pumping lines. This calculator provides a first-pass estimation of the molecular flow conductance for a thin orifice, allowing engineers to quickly assess whether the orifice or the downstream plumbing will dominate the overall effective pumping speed. It uses the fundamental formula: C = A * sqrt((R*T) / (2*pi*M)) which applies for a thin orifice in the molecular flow regime (Kn > 1).
The tool calculates the conductance live as you input the aperture area, gas molar mass, and temperature, displaying results in both L/s and m³/s. It also includes an optional check for wall thickness against the equivalent circular diameter to warn when the 'thin orifice' assumption might be stretched.
Q: What conductance does a 1 cm² orifice have for nitrogen at 293 K?
A: With A = 1×10⁻⁴ m², M = 0.028014 kg/mol and T = 293 K, C = A·√(RT/2πM) works out to about 0.0118 m³/s, i.e. roughly 11.8 L/s.
Q: How much more conductance does hydrogen give than nitrogen through the same aperture?
A: C scales as 1/√M, so H₂ at 2.016 g/mol gives √(28.014 / 2.016) ≈ 3.7× the nitrogen value at the same temperature.
Q: What does the "wall thickness > 0.1 × diameter" warning mean?
A: The formula assumes a zero-length thin orifice; the tool compares the wall thickness you enter against 0.1 × the equivalent circular diameter d = 2√(A/π) derived from your area and flags the result when that limit is exceeded.
Q: Can this conductance be used at any pressure?
A: Only in the molecular flow regime where Kn > 1; the tool takes no pressure input, so the regime has to be confirmed separately before the number is applied.